8x^2-2x=(2x+1)(2x-3)

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Solution for 8x^2-2x=(2x+1)(2x-3) equation: 



8x^2-2x=(2x+1)(2x-3)

We move all terms to the left:

8x^2-2x-((2x+1)(2x-3))=0

We multiply parentheses ..

8x^2-((+4x^2-6x+2x-3))-2x=0



We calculate terms in parentheses: -((+4x^2-6x+2x-3)), so:

(+4x^2-6x+2x-3)

We get rid of parentheses

4x^2-6x+2x-3

We add all the numbers together, and all the variables

4x^2-4x-3

Back to the equation:

-(4x^2-4x-3)



We add all the numbers together, and all the variables

8x^2-2x-(4x^2-4x-3)=0

We get rid of parentheses

8x^2-4x^2-2x+4x+3=0

We add all the numbers together, and all the variables

4x^2+2x+3=0

a = 4; b = 2; c = +3;
Δ = b2-4ac
Δ = 22-4·4·3
Δ = -44
Delta is less than zero, so there is no solution for the equation

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